Complete The Drawing Of The Product Of The Diels–Alder Reaction, Ignoring Stereochemistry.
Complete The Drawing Of The Product Of The Diels–Alder Reaction, Ignoring Stereochemistry.. I labelled the substituents on the diene $\mathrm{r^t}$ and $\mathrm{r^c}$, for trans and cis respectively, to describe their position with respect to the single bond in the middle of the diene. Location of substituents and their stereochemistry follow from several.
Then draw the product of the reaction in the oneclass: • you do not have to consider stereochemistry. For me, the most foolproof way to identify the endo and exo products is to look at the stereochemistry in the product.
Then Draw The Product Of The Reaction In The Oneclass:
• in cases where there is more than one answer, just draw one. In the core reaction, a diene reacts with an alkene (called the dienophile )to produce a cyclohexene ring. • if your product is a bridged bicyclic, draw it as a flat molecule, and do not use wedge bonds for the bridge.
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Location of substituents and their stereochemistry follow from several. The reaction is concerted (bond breaking and forming occur simultaneously) and therefore results in high stereoselectivity (products with predictable stereochemistry). • you do not have to consider stereochemistry.
For Me, The Most Foolproof Way To Identify The Endo And Exo Products Is To Look At The Stereochemistry In The Product.
I labelled the substituents on the diene $\mathrm{r^t}$ and $\mathrm{r^c}$, for trans and cis respectively, to describe their position with respect to the single bond in the middle of the diene.